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0 100 0 66.187.99.2 So, Here is my code: import sys,re from urllib.request import urlopen,urlretrieve from bs4 import BeautifulSoup import pandas as pd import numpy as np import numpy as np from random import choice from itertools import permutations print (" Running from {}".format(sys.argv[0])) url=sys.argv[1] try: f = urlopen(url) print ("Opened!",f.code) soup = BeautifulSoup(f,'lxml') print("found data") data = soup.find('div',{'class':'data'}) for row in data.findAll('tr'): for cells in row.findAll('td'): for col in cells: if col.get_text(): print (col.get_text(), end=" ") else: pass except: print ("Error! Could not load from {}".format(url)) print ("Done!") A: I should add that your original code isn't running quite right. You were only extracting data from the first row of the table, and then looping through every cell. But you also tagged the question with [python-2.7], which means you're looking for answers to Python 2.7 code, and I thought I'd mention that the below is Python 3 only. The 2.7 way of doing this would be: import sys,re from urllib.request import urlopen,urlretrieve from bs4 import BeautifulSoup import pandas as pd import numpy as np import numpy as np from random import choice from itertools import perm

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